What are the odds if you already know 47% favor the measure that you have

to know why 50% would? Weren't you happy with 47%? It's 99% probable that only 43% would NOT be in favor of the measure and 10% can't decide. If you wanted the measure to succeed, hadn't you already won?

In response to this post by Tafkam Hokie

Posted: 01/21/2022 at 09:53AM

Statistics peeps, pop quiz -- Tafkam Hokie 01/21/2022 09:38AM

TOS…please delete ** -- VT Pops 01/21/2022 10:55AM

Standard deviation and the sample size would allow you to calculate this. -- Late 80s Hokie 01/21/2022 10:40AM

Depends on where you're drawing the sample from? ** -- Hokie CPA 01/21/2022 10:38AM

You were on the right track. It is a binomial distribution (not bimodal -- jmanatVT 01/21/2022 10:36AM

I'll do one better. Here is waht looks a heck of a lot like an AP exam's -- jmanatVT 01/21/2022 10:59AM

Take the integral? ** -- Kudelski 01/21/2022 10:29AM

I was told there would be no math ** -- santafe 01/21/2022 10:18AM

Reminds me of Fundamentals of Engineering exam "Part A" toward PE license -- TomTurkey 01/21/2022 12:23PM

According to Douglas Addams, the answer is 42. ** -- Hokie CPA 01/21/2022 10:08AM

Man with empty stomach only has one problem. -- Coach McGuirk 01/21/2022 09:52AM

60% of the time it works every time.** -- VT Pez4Life 01/21/2022 09:43AM

I would flip a coin ** -- bigbadbird 01/21/2022 09:43AM

Well, The Lounge really is the AP TSL message board. ** -- Stork 01/21/2022 09:39AM

There are a lot of smart people here -- Tafkam Hokie 01/21/2022 09:46AM

Despite much evidence to the contrary -- WestyHokie 01/21/2022 10:17AM

What are the odds if you already know 47% favor the measure that you have -- PhotoHokieNC 01/21/2022 09:53AM

What are the odds if you already know 47% favor the measure that you have

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